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9s^2-8s-9=0
a = 9; b = -8; c = -9;
Δ = b2-4ac
Δ = -82-4·9·(-9)
Δ = 388
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{388}=\sqrt{4*97}=\sqrt{4}*\sqrt{97}=2\sqrt{97}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{97}}{2*9}=\frac{8-2\sqrt{97}}{18} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{97}}{2*9}=\frac{8+2\sqrt{97}}{18} $
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